Ksp Ag3Po4. That will be equal to the concentration of a g. By definition, the solubility product constant, ksp, is equal to ksp = [ag+]2 ⋅ [so2− 4] in your case, this will be equal to ksp = (2s)2 ⋅ s = 4s3 rearrange to solve for s, the molar.
Expert answer 100% (14 ratings) transcribed image text: Now we can find the value of k. Ksp of ag3po4 = 2.6×10−18 2.6 × 10 − 18.
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Calculate the solubility of silver phosphate, ag3po4, in pure water. What is the solubility of silver phosphate in a solution which contains. Calculate the solubility of silver phosphate, ag3po4, in pure water. Now we can find the value of k.